2v^2=-14v

Solution for 2v^2=-14v equation:

2v^2=-14v

We move all terms to the left:

2v^2-(-14v)=0

We get rid of parentheses

2v^2+14v=0

a = 2; b = 14; c = 0;
Δ = b2-4ac
Δ = 142-4·2·0
Δ = 196
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{196}=14$
$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(14)-14}{2*2}=\frac{-28}{4}
=-7
$
$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(14)+14}{2*2}=\frac{0}{4}
=0
$